-0,7=-0,012(x^2)+0,01x

Solution for -0,7=-0,012(x^2)+0,01x equation:

-0.7=-0.012(x^2)+0.01x

We move all terms to the left:

-0.7-(-0.012(x^2)+0.01x)=0

We get rid of parentheses

0.012x^2-0.01x-0.7=0

a = 0.012; b = -0.01; c = -0.7;
Δ = b2-4ac
Δ = -0.012-4·0.012·(-0.7)
Δ = 0.0337
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.01)-\sqrt{0.0337}}{2*0.012}=\frac{0.01-\sqrt{0.0337}}{0.024}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.01)+\sqrt{0.0337}}{2*0.012}=\frac{0.01+\sqrt{0.0337}}{0.024}
$